用foreach语句计算数组中的奇数和偶数之和。
int[] a=new int[]{1,2,3,4,5,6,7,8,9,10};

int[] a=new int[]{1,2,3,4,5,6,7,8,9,10};
int sum1 = 0;//(奇数和)
int sum2 = 0;//(偶数和)
foreach(int i in a)
{
if(i%2 != 0)
{
sum1 += i;
}
else
{
sum2 += i;
}
}
Console.WriteLine(sum1);
Console.WriteLine(sum2);

谢谢