<%
j=0
for i=0 to 10
do while j>(i+1)*10
Content(i)=Content(i)&line(j)
j=j+1
l oop

Response.Write Content(i)
Next
%>
我想实现的功能是:
如果line里面有100个的话,就是line(0)到line(99)
line(0)到line(9)存到Content(0)
line(10)到line(19)存到Content(1)
line(20)到line(29)存到Content(2)
line(30)到line(39)存到Content(3)
line(40)到line(49)存到Content(4)
line(50)到line(59)存到Content(5)
line(60)到line(69)存到Content(6)

.........

[此贴子已经被作者于2005-12-7 15:46:12编辑过]